Example

Problem: If enough air was removed from the tube to produce an air pressure of 9.7 psi above the water in the tube, how far will the water rise in the tube?

Solution: To maintain the 14.7 psi at the outside water surface level, the water in the tube must produce a pressure of 14.7 psi - 9.7 psi = 5.0 psi. The height of the column of water that will produce 5 psi is:

9.4 STATIC WATER (WATER AT REST)

Stevin's law states: "The pressure at any point in a fluid at rest depends on the distance measured vertically to the free surface and the density of the fluid." Stated as a formula this becomes:

where:

p = pressure in pounds per square foot (psf). w = density in pounds per cubic foot (lb/ft3). h = vertical distance in feet.

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