Chapter

3.2 (a) pR. (b) and (c) Let 1/T = x, then take the partial with respect to x.

3.3 kt = 1/p; to get kq use pVY = p0vY; result 1/yp.

3.7 T = 205.1 K. AT = -67.9K. Therefore, AU = 48.7 J = W, since Q = 0.

3.10 1.202kgm-3. Q = -7500J. Use the mass of the dry air only as an approximation. AT = 8.7 K.

3.12 0.02 K kg-1 s-1, 20Jkg-1 s-1, AU per unit time = 14.3 J kg-1 s-1.

3.13 (a) 12,500 kg. (b) Mass of an "air" molecule = 0.029/Na = 4.82 x 10-26 kg. N = 2.6 x 1029molecules. (c) 1.3x1044.

3.14 vsound = *JRT for isothermal; VYRT, Y = 1.40 for adiabatic compression waves.

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