From the limit of technology, Mg(0H)2 = 16 mg/L as CaC03 will dissolve. The given concentration of 1.0 meq/L of magnesium is equal to 50 mg/L as CaC03.

Therefore, figCa = 1 - 550 = 0.68; Mr = 303.75 kg/d; MmgHCO3 = 0

[Na+Leq = [Na+Lef 18.9: [Na+]meq,inf = 2 meq/L MsodAsh = 3300.59 kg/d Therefore,

50 meq/L Ans

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