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Therefore, ions are balanced. Ans

(b) M CaO = M CaOCaHCO3 + M CaOMgHCO3 + M CaOMgCa + M CaOCO2 + M CaO Excess M CaOCaHCO3 = 0.35 f CaHCO3 MT CaHCO3 :

Removal of calcium bicarbonate takes precedence. Therefore, meq/L of Ca(HCO3)2 = 2.5

fCaHCO = - 25 ' = 0.88; 0.3 meq/L is the limit of technology of calcium carbonate.

= 62.5C20.05)Ca(HCCO3)2 = 62.5(20.05)(^ffi61*) = 5065.63 kg/d Therefore, MCaOCaHCO = 0.35 (0.88)(5065.63) = 1560.21 kg/d

MCaOMgHCO3 = °.77 f MgHCO3 MTMgHCO3 = 0 M CaOMgCa = 2.30 f MgCa MT Mg:

f MgCa = ^ "I032 = 0.68; 0.32 meq/L is the limit of technology of magnesium hydroxide

Mt Mg = 1.0(i000)(25,000) = 25 kgeq/d = 25( 12.15) = 303.75 kg/d Therefore, MCaOMgCa = 2.30(0.68)(303.75) = 475.07 kg/d

MCaOCO2 = 1.27 (M co2) = 1.27 (22.0)(JL)(25,000) = 698.5 kg/d MCaOExcess = 0.028 ¥ kg = 0.028(25,000) = 700 kg/d

Therefore, MCa0 = 1560.21 + 0 + 475.07 + 698.5 + 700 = kg/d of pure lime = ^^ = 3815.31 kg/d of lime Ans

(c) MsodAsh = MsodAshCa + MsodAshCaMg MsodAshCa = 2.65 /CaMTCa:

/ca = 1 Mt ca = (3.99 - 2.5)(20.05) (d-) (25,000) = 745.75 kg/d Therefore, MsodAshc = 2.65(1.0)(745.75) = 1976.24 kg/d

MsodAshCaMg = 4.36 /MgCaMTMg:

= 4.36(1.0)(303.75) = 1324.35 kg/d Therefore, MsodAsh = 1976.24 + 1324.35 = 3300.59 kg/d of pure soda ash

330059 = 3883.05 kg/d of soda ash Ans 0.85

(d) Msolids = MsolidsCarb + MsolidsNonCarb + MCaCO3CO2

MsolidsCarb = M CaCO3CaHCO3 + M MgOHMgHCO3 + M CaCO3MgHCO3:

MCaCO3CaHCO3 = 1.23 /CaHCO3MTCaHCO3 :

Therefore, M^co3chco3 = 1.23(0.88)(5065.63) = 5483.04 kg/d

M MgOHMgHCO3 = 0.40 / MgHCO3 MTMgHCO3 = 0 M CaCO3 MgH CO3 = 1.37 / MgHCO3 MT MgHCO3 = 0

Therefore, MsolidsCarb = 5483.04 + 0 + 0 = 5483.04 kg/d

MsolidsNonCarb = MMgOHMgCa + M CaCO3Ca + M CaCO3MgCa:

MMgOHMgCa = 2.40 /MgCaMT Mg = 2.40(0.68)(303.75) = 495.72 kg/d MCaCO Ca = 2.49 /cMt ca = 2.49(1)(745.75) = 1856.92 kg/d M caC03MgCa = 4.11 /MgCa Mt Mg = 4.11(0.68)(303.75) = 848.92 kg/d Therefore, MsolidsNonCarb = 495.72 + 1856.92 + 848.92 = 3201.56 kg/d M caco3co2 = 2.27 (M co2) = 2.27(22.0) (25,000) = 1248.5 kg/d

Therefore, Msolids = 5483.04 + 3201.56 + 1248.5 = 9933.1 kg/d Ans

Therefore, Vsl =

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