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Depth of tank, H = = 2.94 m. Add freeboard of 0.3 m

Actual depth of tank = 2.94 + 0.3 = 3.24, say 3.3 m

Volume of tank = LWH = 20(106.46)(2.94) = 6259.8 m3 ^ 6210 m3

Let there be 10 tanks; thus, width per tank = 10.65 m, say 10 m Dimension for each tank: length = 20 m, width = 10 m, depth = 3.3 m Ans

Actual detention time = 20(10)(2.94)/((0.69/10)(60)(60)) = 2.37 h. Note that the freeboard of 0.3 m does not hold water; thus, 2.94 m is used in the calculation.

Now, determine the amount of recirculation required at minimum flow.

V = 20(10)(2.94) = 588 m3, for one tank Q = 0.3(20,000) = 3,

Therefore,

Qr = (2.37)(60)(60) = °.°62 m /s AnS Example 5.11 Repeat the previous example for a circular settling basin.

Solution:

Considering overflow rate,

Overflow area of tank, = ^ = 2129.14 D = 52.07 m, too large

Use two tanks, therefore —7- = ——1— D = 36.82 m, too large How To Bolster Your Immune System

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